Dos中怎么获取系统时间

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代码如下:

rem DOS get current time rem ======================= rem get yyyy/mm/dd set mydate=%DATE:~0,10% echo %mydate% rem ======================= rem get yyyy set yyyy=%DATE:~0,4% echo %yyyy% rem ======================= rem get mm set mm=%DATE:~5,2% echo %mm% rem ======================= rem get dd set dd=%DATE:~8,2% echo %dd% rem ======================= rem get yyyy-mm-dd set curdate=%yyyy%-%mm%-%dd% echo %curdate%

其实bat中获取时间就是利用截取日期字符串的方法DOS下有字符处理的方法的，总结如下： 在这个日期格式下：”2013-07-22 星期一”， 这个%DATE:~0,10%得到的是2013-07-22 说明：DATE为系统变量，“:”表示开始处理前面的字符串“~0,10”表示从第0个字符开始取10个字符。 输出：

C:\Documents and Settings\Administrator>rem DOS get current timeC:\Documents and Settings\Administrator>rem =======================C:\Documents and Settings\Administrator>rem get yyyy/mm/ddC:\Documents and Settings\Administrator>set mydate=2013-07-22C:\Documents and Settings\Administrator>echo 2013-07-222013-07-22C:\Documents and Settings\Administrator>rem =======================C:\Documents and Settings\Administrator>rem get yyyyC:\Documents and Settings\Administrator>set yyyy=2013C:\Documents and Settings\Administrator>echo 20132013C:\Documents and Settings\Administrator>rem =======================C:\Documents and Settings\Administrator>rem get mmC:\Documents and Settings\Administrator>set mm=07C:\Documents and Settings\Administrator>echo 0707C:\Documents and Settings\Administrator>rem =======================C:\Documents and Settings\Administrator>rem get ddC:\Documents and Settings\Administrator>set dd=22C:\Documents and Settings\Administrator>echo 2222C:\Documents and Settings\Administrator>rem =======================C:\Documents and Settings\Administrator>rem get yyyy-mm-ddC:\Documents and Settings\Administrator>set curdate=2013 -07 -22C:\Documents and Settings\Administrator>echo 2013 -07 -222013 -07 -22C:\Documents and Settings\Administrator>

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